Question

construct a triangle pqr in which pq =8cm angle R=60° and the median rg from r to pq is 5.8cm​

Answer 1

Answer:

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Step-by-step explanation:

Emf-xxcj-cqz ajao sex k liye

Answer 2

Answer:

Step-by-step explanation:

Base AB = 5cm Median CM to the base = 4cm & vertical angle <C = 60°

Steps: 1: Draw a ray & cut segment AB = 5 cm

2: Construct BAD = 60° at point A on AB.

3: At A on AD , construct a perpendicular.

4: Now, draw perpedicular bisector of AB, which intersects the perpendicular of previous step at O

5: Taking O as centre & OA radius, draw a circle. This circle passes through A& B. And AD will be the tangent to this circle. Because radius OA is perpendicular to AD.

6 : M as centre, & 4 cm radius draw an arc, which cuts the arc of major segment at C

7: Join A,C & B,C.

ABC is the required triangle..

Justification: < DAB = 60° , which is formed by chord AB & tangent AD to the circle,

=> <DAB = < ACB = 60°. ( by alternate segment theorem, which states that angle formed by a tangent to the chord = angle formed by the chord at the alternate segment of the circle. And here we have constructed median AM = 4cm & AB = 5 cm..