Question

construct a triangle pqr in which PQ +QR RP =10cm , angle Q=30°,angle R =60° with justification

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Answer 1

Step-by-step explanation:

Steps of Construction:

1. Draw a line segment AB=11 cm. (=PQ+QR+RP).

2. At A, construct an angle of 30

∘

and at B, an angle of 90

∘

.

3. Bisect these angles. Let the bisectors of these angles intersect at a point P.

4. Draw perpendicular bisectors DE of AP to intersect AB at Q and FG of PB to intersect AB at R.

5. Join PQ and PR. Then, PQR is the required triangle.