Question

construct a triangle PQR in which, /_Q = 60° /_R=45² and PQ+QR+PR = 13.3 cm.
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Answer 1

Answer:

Step 1: Draw a line segment AB of 11cm

XY+YZ+ZX=11cm

Step 2: Using a protractor mark 30

∘

at A, i.e ∠PAB and ∠QBA as 90

∘

Step 3: Bisect 30

∘

at A, i.e ∠PAB and ∠QBA at point X.

Step 4: Join XZ and make XZ perpendicular to AB.

Step 5: Draw perpendicular bisector of AX i.e ST.

Step 6: Mark the point Y where ST and AB intersect. Join XY

∴ We get △XYZ

solution

Answer 2

Answer:

Ask the mam for explaining ok

Step-by-step explanation:

∆XYZ