construct a triangle pqr in which qr =5 cm angle q =60°pr+pq=7.5
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1.Draw base BC=7cm
2.Let's draw ∠B=75
∘
.Let the ray be BX
3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D
4.Join $$CD$
5.Now, we will draw perpendicular bisector of CD
6.Mark point A where perpendicular bisector intersects BD
7.Join AC
Result:△ABC is the required triangle.
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