Question

Construct a triangle PQR in which QR=6 cm,PQ=4.4 cm and PR=5.3 cm . Draw the bisector of angle P.

Answer 1

steps
1)draw line QR of given 6 centimetre .
2)draw an arc of 4.4 cm from the point Q .
3)now draw an another arc from point a R 5.3 CM .
4)where to both arcs of R and Q intersect will be the point P .
5)now triangle pqr is constructed .
6)from point P draw any arc.
7)where the arc will intersect in line segment PQ &QR bisect it by compass by taking same arc.
8)join the intersection point with point P which is angle bisector of angle P.

Answer 2

Answer:

Given, to constant a ΔPQR

in which QR=6cm, PQ=4.4cm & PR=53cm

Also given to draw the bisector of angle P.

Construction steps:-

(1) Firstly, draw a line segment QR=6cm.

(2) Now, taking 'Q' as a point draw an arc with 4.4cm.

(3) Now similarly from 'R' cut the previous arc with 5.3cm.

(4) Now, name the arc intersection point as 'p'.

(5) Join the points, thus ΔPQR is formed.

(6) From point 'p' draw an arc, such that it intersects line segment QR.

(7) Now from 'Q' or 'R' cut the arc.

(8) Now joint the intersection point of arc to P.

(9) Having joined the intersection point, angle bisector of 'P' is obtained.

(10) Thus, required figure is obtained.

solution