Question

Construct a triangle PQR, in which QR= 6cm, <Q =600 and PR – PQ = 2cm.







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Answer 1

The answer is written down idiot!

Step-by-step explanation:

Draw the base QR=6 cm. ...

Cut the line segment QS equal to PR-PQ=2 cm , from the ray QX extended on opposite side of base QR.

Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

Let P be the intersection point of SX and perpendicular bisector AB.

Now if you're reading this then let me remind you that you are simply wasting your time and literally disrespecting my efforts to serve you with this answer. What are you still reading? Jot that down in your copy! Why are you still reading man? You are completely useless. Let me stop writing then. See you are still reading you time wasting piece of #*i@!!!!