construct a triangle pqr in which QR is equal to 7 cm angle Q is equal to 75 degree and PQ + PR is equal to 13 cm
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construct a triangle pqr in which QR is equal to 7 cm angle Q is equal to 75 degree and PQ + PR is equal to 13 cm
With the given data multiple triangles can be constructed
Draw QR = 7 cm
and draw a line at angle of 75 deg
now length of PQ can be drawn as
PQ = 5.363 cm then join PR = 7.637 cm
how we get these dimensions
PR² = QR² + PQ² - 2 QR PQ∠Q
=> (13 - PQ)² = 7² + PQ² - 2 * 7 PQ Cos 75°
=> 169 + PQ² - 26PQ = 49 + PQ² - 14PQ(0.259)
=> 120 = 26 PQ - 3.626PQ
=> PQ = 5.363
PR = 13 - PQ
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