Question

construct a triangle PQR, PQ=4 cm ,QR= 6cm angle Q =110 degree ​

Answer 1

Answer:

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.

Answer 2

Step-by-step explanation:

1.

Recognize the hkl values for the first few peaks:

100, 110, 111, 200, 210, 211, 220, etc.

2.

Calculate the interplanar spacing, d, for each peak:

1/d2 = (h2 + k2 + l2)/a2

3.

Use Bragg’s Law to determine the 2θ value:

λ = 2dhkl sin θhkl

hkl = 100

1/d2 = (12 + 02 + 02)/(3.90 Å)2 → d = 3.90 Å

sin θ100 = 1.54 Å/{2(3.90 Å)} → θ = 11.4° (2θ = 22.8°)

hkl = 110

1/d2 = (12 + 12 + 02)/(3.90 Å)2 → d = 2.76 Å

sinθ110 = 1.54 Å/{2(2.76 Å)} → θ = 16.2° (2θ = 32.4°)

hkl = 111

1/d2 = (12 + 12 + 12)/(3.90 Å)2 → d = 2.25 Å

sin θ111 = 1.54 Å/{2(2.25 Å)} → θ = 20.0° (2θ = 40.0°)