construct a triangle PQR such that :answer my question and become brainleast 3 bit
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to construct a triangle PQR of QR =4.4 cm , angle R= 30° and angle Q= 75° :-
1. draw a base line QR of given measurement
2. construct an angle of 30° at point R as angle XQR= 30° .
3.construct an angle of 75° at point Q as angle YQR =75°.
(to construct an angle of 75° firstmake two angle of 90° n 120° at point Q then bisect this angle u will get YQR as 75° ).
4. where the lines YQ AND XR cuts each other label as P .
5. Hence PQR is the req . triangle . where PQ measures 3.5 cm and PR measures6.3 cm.
1. draw a base line QR of given measurement
2. construct an angle of 30° at point R as angle XQR= 30° .
3.construct an angle of 75° at point Q as angle YQR =75°.
(to construct an angle of 75° firstmake two angle of 90° n 120° at point Q then bisect this angle u will get YQR as 75° ).
4. where the lines YQ AND XR cuts each other label as P .
5. Hence PQR is the req . triangle . where PQ measures 3.5 cm and PR measures6.3 cm.
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