Question

Construct a triangle PQR such that PQ = 5 cm, PR = 4.3 cm and angleP = 60°.​

Answer 1

QUESTION ⏬

Construct a triangle PQR such that PQ = 5 cm, PR = 4.3 cm and angleP = 60°.

ANSWER ⏬

Steps of Construction:

(i) Draw a line segment that is sufficiently long using a ruler.

(ii) Locate points Q and R on it such that QR=5.2cm.

(iii) At Q, construct a line segment QM, sufficiently large, such that ∠MQR at 60

∘

use protractor to measure 60

∘

(iv) With Q as centre and radius 4cm, draw the line cutting QM at P, join PR.

Then PQR is the required triangle.

Answer 2

Explanation:

Construction steps : 1 ) Draw a line segment PB = 4cm 2 ) Construct a ray QX such that <PQX = 60° 3 ) Take see pic