Question

construct a triangle PQR such that QR=7 cm.,QP=4 cm and angle Q=30°.​

Answer 1

Answer:

1)Take QR=7 as base

2)Draw angle RQX=30degree

3)Take 4cm as radius draw an arc which intersects QP at d

u can take any word like d

4)Then join d and R

Then the required triangle can be constructed

Answer 2

$\triangle PQR$ is the required triangle.

Step-by-step explanation:

Given,

Construct a $\triangle PQR$ such that $QR=7\ cm,QP=4\ cm\ and\ \angle Q=30\ degree$

Following steps:

• Draw a line segments $QR=7\ cm$ using scale.
• At $Q$, draw an angle $30\ degree$ using protector like $\angle RQX=30\ degree$
• $Q$ as center and $4\ cm$ as radius draw an arc $P$ on line $QX$
• Join $PR$

Hence, $\triangle PQR$ is the required triangle.