construct a triangle PQR ,such that sum of all its sides is 10.5 cm and Angle B =60 and C=40
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it's very simple just we have to draw a triangle suppose we have taken the length on the scale as 10.5 centimeter so we will take a scale and take a measurement as 10.5 cm and draw one side has 10.5cm we will draw on paper by measuring this length from the scale then you have to draw angle 60 take our protector and keep in the one point of 10.5 CM line drawn by you now marks 60 degree from protector and draw the line then the end of the point where we will draw 40 degree now we will keep the protector in the point of 60 degree for the length of the point of the 10.5 CM then we will draw the angle 40 degree from The protector we will mark the point using a protector articulate 40 degree then will draw the line and it will form a triangle given in the question same to same
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