construct a triangle pqr with angle p =60 degree and q = 30 degree and pq = 4.8 cm . measure angle r .what kind of triangle is this ?
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The angle is 90° and it is a right angled triangle
Construction steps:
- Draw a line segment pq of 4.8 cm
- Measure 60° on a compass and cut an arc by putting on point p
- Measure 30° on a compass and cut an arc by putting on point q
Now, as we know the the sum of all the internal angles of a triangle is 180°.
Hence,
60 + 30 + x = 180 (where x is the angle of r)
90 + x = 180
x = 90°
Also, the triangle which is having an angle 90° is a right angled triangle.
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