Question

Construct a triangle PQR with PQ= 6cm, QR= 4cm, and Q =
100°​

Answer 1

Step-by-step explanation:

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90

⋅

and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60

⋅

and at R, a ray making an angle 120

⋅

which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.

Answer 2

Step-by-step explanation:

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