Question

construct a triangle pqr with pq = 7.5 cm angle rpq=45° ,rqp =45° . measure the third angle . what kind of triangle is it

Answer 1

It is a isosceles right angle triangle.
It is 45°-45°-90° triangle.
PQ=QR.....(isosceles triangle theorem)
PQ ×√2 = PR
7.5√2 = PR .... (45°-45°-90° THEOREM ).
hope this helps you :-))))
don't forget to do it brainleist.

Answer 2

Answer:

Third angle = 90° and pqr is an isosceles triangle.

Step-by-step explanation:

In Δ pqr,

∠rpq = 45° , ∠rqp = 45°

Now, Using angle sum property of a triangle which states that sum of all the angles of a triangle is 180°. We get,

∠rqp + ∠rpq + ∠prq = 180°

45° + 45° + ∠prq = 180°

⇒ ∠prq = 90°

Since the two angles :  ∠rqp and ∠rpq are equal. So, the opposite sides to both the angles are also equal ⇒ pr = qr

Now, In Δpqr the two sides are equal, so Δpqr is an isosceles triangle.