Question

Construct a triangle similar to a given triangle ABC such that each of its sides is 5/7th of the corresponding sides of triangle ABC. it is given that AB =5cm, BC=7cm and angle ABC =50 degree

Answer 1

Answer:

angle ABC = 50 and ABC is a required triangle

Answer 2

Given :   triangle ABC  

AB=5 cm  BC =7cm  and ∠ABC=50°

To Find : Construct a triangle similar to given triangle ABC  such that each side is 5/7 of the corresponding sides of triangle

Solution:

Step 1 : Draw  a line segment AB = 5 cm

Step 2 : Draw an angle of 50° at B on AB using protractor

Step 3 : Take a length of  7 cm  from B on angle drawn and mark as C

Step 4 : Join AC

ΔABC is  constructed

Draw an acute angle ∠BAX

Mark   7 points at equal distance from B one be one at ray BX

Join 7th point with B

Draw a line parallel to above line from 5th point and intersecting  AB at B'

Draw a line parallel to BC passing passing through B ' and intersecting  AC at C'

ΔAB'C'  is 5/7  of ΔABC

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