Construct a triangle Similar to a given triangle PQR With its sides equal to of the corresponding Sides of triangle PQR ( Scale factor < 1 ).
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Answer:
Given a triangle ΔPQR. We have to construct another triangle whose sides are 7/3 of the corresponding sides of the given ΔPQR. Steps of construction: (1) Draw any ray QX making an acute angle with QR on the opposite side to the vertex P. (2) Locate 7 points (the greater of 7 and 3 in 7/3) Q1, Q2, Q3, Q4, Q5, Q6, and Q7 so that QQ2 = Q1 Q2 = Q2 Q3 = Q3 Q4 = Q4 Q5 = Q5 Q6 = Q6 Q7 (3) Join Q3 to R and draw a line segment through Q7 parallel to Q3 R intersecting the extended line segment QR at R’. (4) Draw a line segment through R’ parallel to PR intersecting the extended line segment QP at P’. Then ΔP’QR’ is the required triangle each of whose sides is 7/3 of the corresponding sides of the given triangle.Read more on Sarthaks.com - https://www.sarthaks.com/945044/construct-triangle-similar-given-triangle-sides-equal-corresponding-sides-triangle-factor