Question

construct a triangle similar to the triangle ABC such that each of its side is 2 by 3 of corresponding sides of triangle ABC it is given that BC=6cm,ab=5cm,AC=4cm
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Answer 1

Step-by-step explanation:

First let's construct $\sf \triangle ABC$

Sides given

• BC=6cm
• AB=5cm
• AC=4cm

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier (6,0)(6,0)(0,0)\qbezier (0,0)(4,3)(4,3)\qbezier (4,3)(4,3)(6,0)\put (4,3.2){\sf A}\put (-0.2,-0.2){\sf B}\put (6.2,-0.2){\sf C}\end{picture}$

Now find sides of triangle PQR

• $\\\qquad\quad\sf {:}\longrightarrow PQ=\dfrac {2}{3}\times 6$

$\\\qquad\quad\sf {:}\longrightarrow PQ=4cm$

• $\\\qquad\quad\sf {:}\longrightarrow QR=\dfrac {2}{3}\times 5$

$\\\qquad\quad\sf {:}\longrightarrow QR=3.3cm$

• $\\\qquad\quad\sf {:}\longrightarrow PR=\dfrac {2}{3}\times 4$

$\\\qquad\quad\sf {:}\longrightarrow PR=3.6cm$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier (6,0)(6,0)(0,0)\qbezier (0,0)(4,3)(4,3)\qbezier (4,3)(4,3)(6,0)\put (4,3.2){\sf P}\put (-0.2,-0.2){\sf Q}\put (6.2,-0.2){\sf R}\end{picture}$