Construct a triangle such that ab+bc+ac=12cm łb=45°,łc=60°measure ab, bc, ac what type of triangle you obtain
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Answer:
Step-by-step explanation:
Draw a line PQ= 12cm (perimeter). Draw PA at half angle B=22 1/2 degrees
and QA at half angle C 30 degrees, meeting each other at A, Draw perpendicular bisector of AP to meet PQ at B; similarly of AQ to meet at C . We get ABC as required triangle .
proof: due to perpendicular bisections, AB=PB and AC=QC, angle B= 45 deg and angle C 60 ; PQ= AB+BC+CA=12
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