Construct a triangle whose base BC = 7 cm, angleB = 75° and AB + AC = 10 cm.
Answers
Answered by
4
Step-by-step explanation:
STEPS OF CONSTRUCTION :
Draw a ray BX and cut off a line segment BC = 7cm; from it.
At B; construct angle YBX = 75°
With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.
Join CD.
Draw Perpendicular bisector PQ of CD intersecting BD at A.
Join AC.
Attachments:
Answered by
2
Step-by-step explanation:
it it may help you
........
...........
.............
Attachments:
Similar questions