Question

The class marks of a frequency distribution are given as follows:15, 20, 25, …The class corresponding to the class mark 15 is :-

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Answer 1

Step-by-step explanation:

Class size = 20 – 15 = 5

Consider a as the lower limit of the required class

Upper limit can be written as a + 5

So we get (a + (a + 5))/ 2 = 20

On further calculation 2a + 5 = 40 So we get

2a = 35

By division a = 17.5

Upper limit a + 5 = 17.5 + 5 = 22.5

Therefore, the required class is 17.5-22.5

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