Question

construct a triangle whose perimeter is 13 and base angles are 60 and 90​

Answer 1

The below given steps will be followed to construct the required triangle.

Step I: Draw a line segment AB of 15cm.

(As XY + YZ + ZX = 15 cm)

Step II: Construct an angle, ∠PAB, of 30° at point A and an angle, ∠QBA, of 90° at point B.

Step III: Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.

Step IV: Draw perpendicular bisector ST of AX and UV of BX.

Step V: Let ST intersect AB at Y and UV intersect AB at Z.

Join XY, XZ.

Answer 2

Answer:

here is your answer

hope it helps you

Step-by-step explanation:

• first draw PQ equal to perimeter i.e 13 cm
• then draw desired angles at P and Q
• draw the angle bisectors of these angles( shown via purple lines in attachment)
• extend the angle bisectors so that they meet at a common point A
• draw perpendicular bisectors of these extend angle bisectors(MN is the perpendicular bisector of AP and XY is the perpendicular bisector of AQ)
• the perpendicular bisectors will meet PQ at B and C
• join A,B,C

triangle ABC is the reqd. triangle