Question

construct a triangle whose perimetre is 15 cm with base angle 90°and30°​

Answer 1

Things need to use: a compass, ruler, protractor
first construct a 60 ° angle by using a compass and make an intersection in the middle to get a a 30°. same goes for the 90° but add the other 30° to the 60° angle. just so you know, 90°= a straight vertical line= a L shape

Answer 2

The below given steps will be followed to construct the required triangle.

Step I: Draw a line segment AB of 15cm.

(As XY + YZ + ZX = 15 cm)

Step II: Construct an angle, ∠PAB, of 30° at point A and an angle, ∠QBA, of 90° at point B.

Step III: Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.

Step IV: Draw perpendicular bisector ST of AX and UV of BX.

Step V: Let ST intersect AB at Y and UV intersect AB at Z.

Join XY, XZ.