Question

construct a triangle with sides are 5cm 6cm and 7cm and then construct another triangle whose side are 4/3 of the corresponding sides of the constructed triangle​

Answer 1

Answer:

Constructing the first triangle:

Step 1: Draw base AB of length 7 cm

Step 2: Place a compass on A and draw an arc of radius 5 cm

Step 3: Place the compass on B and draw an arc of radius 6 cm such that it intersects the arc drawn in step 2.

Step 4: Mark the intersection of the two arcs as C and join A−C and B−C

△ABC is the given triangle.

Let △PAQ be the required triangle.

Step 1: Draw a ray AX from point A on the opposite side of C, making an acute angle with AB.

Step 2: Mark 7 equidistant points A

1

,A

2

,A

3

,...,A

7

on ray AX.

Step 3: Join A

5

to B.

Step 4: Draw A

7

Q parallel to A

5

B and mark the point on the extension of line AB as Q.

Step 5: Draw PQ parallel to BC and mark the intersection point on the extension of AC as P.

△PAQ is the required triangle.

Step-by-step explanation:

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