Question

evaluate the zeroes of the polynomial 2x square-16​

Answer 1

Answer:

$2x { }^{2} - 16 \\ \\ 2x {}^{2} - 16 = 0 \\ 2 {x}^{2} = 16 \\ 2x = \sqrt{16 } \\ 2x = 4 \\ x = 4 \div 2 \\ x = 2$

Step-by-step explanation:

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Answer 2

Given,

$\[ = 2{x^2} - 16\]$

Solution,

Calculate the zeros.

$\[\begin{array}{l}2{x^2} - 16 = 0\\ \Rightarrow 2{x^2} = 16\\ \Rightarrow {x^2} = 8\\ \Rightarrow x = \pm 2\sqrt 2 \end{array}\]$

Hence the zeros of the polynomial is $\[ \pm 2\sqrt 2 \]$