Math, asked by gboy13522, 3 months ago

construct a triangle with sum of all sides 12 cm and two base angle are 45 and 60 degree each.write the step of construction​

Answers

Answered by yashikagera16
0

1)Draw a line segment PQ = AB + BC + CA = 12 cm.

2)Make ∠ LPQ= 45° and ∠ MQP = 60°

3)Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.

4)Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.

5)Join AB and AC.

Answered by sanaarmygirl1997
1

Answer:

Draw a line segment PQ = AB + BC + CA = 12 cm.

Make ∠ LPQ= 45° and ∠ MQP = 60°

Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.

Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.

Join AB and AC.

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