Question

Construct a triangle xyz in which angle y =30 degree ,angle=90 degree and xy+yz+zx=11cm

Answer 1

hey______________
1.Draw a line segment PQ equal to XY + YZ + ZX = 11 cm.
2.Make ∠ LPQ = ∠Y = 30° and ∠ MQP = ∠Z = 90°
3.Bisect ∠ LPQ and ∠ MQP. Let these bisectors intersect at a point X .
4.Draw perpendicular bisectors of line XP and XQ
5.Let AB intersect PQ at Y and CD intersect PQ at Z.
6.Join XY and XZ
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hoping u will make your diagram ......

Answer 2

hey here is your answer

Steps of Construction:
Step 1: A line segment PQ = 11 cm is drawn. (XY + YZ + ZX = 11 cm)
Step 2: An angle, ∠RPQ = 30° is constructed at point A and an angle ∠SQP = 90° at point B.
Step 3: ∠RPQ and ∠SQP are bisected . The bisectors of these angles intersect each other at point X.
Step 4: Perpendicular bisectors TU of PX and WV of QX are constructed.
Step V: Let TU intersect PQ at Y and WV intersect PQ at Z. XY and XZ are joined.
Thus, ΔXYZ is the required triangle.

I know its doesn't help so much as u want but sorry...