CONSTRUCT A TRIANGLE XYZ IN WHICH ∠Y =30° ,∠Z=90° AND XY+YZ+ZX=11cm......
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Step-by-step explanation:
Step 1: Draw a line segment AB of 11cm.
Step 2: Draw ∠DAB = Y = 30o and ∠FBA = ∠Z = 90o
Step 3: Draw the angle bisector of ∠DAB and ∠EBA which intersect each other at x
Step 4: Draw the perpendicular bisector XA and XB which intersect AB at Y and Z respectively.
Step 5: Join XY and XZ
XYZ is the required triangle
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