Math, asked by navdeep4321lakhia, 1 year ago

CONSTRUCT A TRIANGLE XYZ IN WHICH ∠Y =30° ,∠Z=90° AND XY+YZ+ZX=11cm......

Answers

Answered by Anonymous
17

Step-by-step explanation:

Step 1: Draw a line segment AB of 11cm.  

Step 2: Draw ∠DAB = Y = 30o and ∠FBA = ∠Z = 90o  

Step 3: Draw the angle bisector of ∠DAB and ∠EBA which intersect each other at x  

Step 4: Draw the perpendicular bisector XA and XB which intersect AB at Y and Z respectively.  

Step 5: Join XY and XZ  

XYZ is the required triangle

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