construct a triangle XYZ in which YZ = 7 cm and Y = 45 and Z = 90. Then construct another triangle whose sides are 2/3 of the corresponding sides of triangle XYZ
Answers
Answered by
4
hey friend i can help u just with the steps. so here are following:
1. draw a line segment YZ of 7 cm.
2. with a protractor draw angle 45 at Y and angle 90 at Z.
3. you will get a triangle XYZ
4. from Y draw a ray with acute angle
5. on the ray with a compasses draw arcs Y1 Y2 N Y3 equidistant from each other that is YY1 = Y1Y2 =Y2Y3
6. join Y3 at Z
7. then draw a line Y2Z' on YZ ll'el to Y3Z
8. draw a line Z'X' ll'el to ZX
9. triangle X'Z'Y is required triangle!!
# i hope it helps u!!
1. draw a line segment YZ of 7 cm.
2. with a protractor draw angle 45 at Y and angle 90 at Z.
3. you will get a triangle XYZ
4. from Y draw a ray with acute angle
5. on the ray with a compasses draw arcs Y1 Y2 N Y3 equidistant from each other that is YY1 = Y1Y2 =Y2Y3
6. join Y3 at Z
7. then draw a line Y2Z' on YZ ll'el to Y3Z
8. draw a line Z'X' ll'el to ZX
9. triangle X'Z'Y is required triangle!!
# i hope it helps u!!
Answered by
2
well the above construction is correct.
I am just showing the diagram.
i hope this helps u
Attachments:
Similar questions