Question

The base BC of an equilateral teiangle ABC lies on y axis .the co ordinat3s of point C are (0,-3).the origin is the mid point of the base .find the co ordinates of point A and B .also find the coordinates of another point D such that BACD is a rhombus

Answer 1

if origin is in mid point of BC then coordinate of B is (0,3) and coordinate of A is the perpendicular distance between A and origin i.e. √6²-3² =3√3 so coordinate of A is (3√3,0) and D is (-3√3,0)