construct a triangle XYZ such that angle Y=105° and XY = YZ =5cm. Anyone pls say how to construct it.
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see u HV given that XY=YZ=5cm
therefore, first draw a horizontal line of 5cm as XY
Then, take a protector and place the midpoint at X and draw a line with the measure of 105°
and then take ur rounder/ compass and measure it with the scale take 5cm bcoz XY=YZ=5cm. Then, place the point of rounder on X make a arc on the angle, name that point as Z, and join Z to Y with the scale. Hence, triangle XYZ is drawn
therefore, first draw a horizontal line of 5cm as XY
Then, take a protector and place the midpoint at X and draw a line with the measure of 105°
and then take ur rounder/ compass and measure it with the scale take 5cm bcoz XY=YZ=5cm. Then, place the point of rounder on X make a arc on the angle, name that point as Z, and join Z to Y with the scale. Hence, triangle XYZ is drawn
Ramya1446:
thank you so much
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