Question

construct a triangle XYZ such that I(XY)=6cm, I(YZ)=4cm, I(XZ)=5cm​

Answer 1

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We are given that triangle XYZ ~ triangle PQR.

Also, in triangle XYZ, YZ = 6 cm, XZ = 5 cm and XY = 4 cm

In triangle PQR, PQ = 4 cm

Since, triangle XYZ ~ triangle PQR

Therefore, XY/PQ = YZ/QR = XZ/PR

So, 4/8 = 1/2

Since ratio of one side of both the triangle is in proportion 1/2, so all sides of both the triangles will have same proportion.

Therefore, YZ/QR = 6/QR =1/2

So, QR = 12 cm

Similarly we can find PR:

XZ/PR = 5/PR = 1/2

Therefore, PR = 10 cm

So we have got both the sides.

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Answer 2

Answer:

We are given that triangle XYZ ~ triangle PQR.

Also, in triangle XYZ, YZ = 6 cm, XZ = 5 cm and XY = 4 cm

In triangle PQR, PQ = 4 cm

Since, triangle XYZ ~ triangle PQR

Therefore, XY/PQ = YZ/QR = XZ/PR

So, 4/8 = 1/2

Since ratio of one side of both the triangle is in proportion 1/2, so all sides of both the triangles will have same proportion.

Therefore, YZ/QR = 6/QR =1/2

So, QR = 12 cm

Similarly we can find PR:

XZ/PR = 5/PR = 1/2

Therefore, PR = 10 cm

So we have got both the sides.

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