Question

Construct a ∆xyz in which ∠y= 60°, ∠z = 45° and xy + yz + zx = 11 cm. Also write the steps of

construction.​

Answer 1

Answer:

Step-by-step explanation:

Construct a ∆xyz in which ∠y= 60°, ∠z = 45° and xy + yz + zx = 11 cm. Also write the steps of  construction.​

∠x + ∠y + ∠z = 180°  ( sum of angles of triangle)

=> ∠x + 60° + 45° = 180°

=> ∠x = 75°

Using Sides sin rule

xy / Sin∠z  = yz / Sin∠x  = zx/Sin∠y =  a

=> xy = a Sin∠z  , yz = a Sin∠x  , zx = aSin∠y

xy + yz + zx = 11 cm

a ( Sin∠z + Sin∠x + Sin∠y) = 11 cm

Using this we can get a

Then we can can get yz

then we can draw YZ line of that length

and draw angles of 60° & 45° from Y & Z points

where they intersect that is the point X

and Hence we can draw triangle