Question

Construct AABC, whose base BC = 4.8 cm and the base angles are 45° and 60°

pls tell the answer ​

Answer 1

Answer:

Step-by-step explanation:

Steps of construction: Construct a line segment PQ = 11.6cm Draw a 45o and bisect it to obtain ∠NPQ Draw a 60o and bisect it to obtain ∠MQP Rays PN and QM intersect at the point A Draw the perpendicular bisectors of PA and QA which intersects PQ at the points B and C Read more on Sarthaks.com - construct-a-abc-whose-perimeter-is-11-6cm-and-the-base-angles-are-45and-60Join the point AB and AC Therefore, △ ABC is the required triangle. Read more on Sarthaks.com construct-a-abc-whose-perimeter-is-11-6cm-and-the-base-angles-are-45and-60