Question

Construct ∆ ABC if ∠A = 600 , ∠ B = 500 and l(AB) = 5cm​

Answer 1

Answer:

The ΔA

′

BC

′

whose sides are

4

3

of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60

∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B

1

,B

2

,B

3

,B

4

on line segment BX.

Step 4: Join B

4

C and draw a line through B

3

, parallel to B

4

C intersecting BC at C

′

.

Step 5: Draw a line through C

′

parallel to AC intersecting AB at A

′

.

The triangle A

′

BC

′

is the required triangle

Answer 2

Draw a line segment AB = 5 cm.

Make a 600 angle from point B and draw BC = 6 cm.

Join A and C to get the triangle ABC.

Dividing the base:

Draw a ray at an acute angle from BA.

Plot 4 points on BA so that BB1 = B1B2 = B2B3 = B33B4.

Join B4 to point A.

Draw a line from B3 parallel B4A so that it meets AB at point A’.

Draw A’C’ || AC.

Triangle A’C’B is the required triangle.

Triangles. If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar

$\color{blue}{ Answered \ by \ Srijan}$