Construct ∆ABC in which BC=4.2cm,^B=30°and AB-1.6cm.
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given
BC=4.2cm
angle B=30°
AB=1.6cm
- draw a line segment BC of length 4.2
- make an angle of 30° at B
- cut BX of length 1.6 with the help of compass and point it as A
- now join the C and A
- triangle is ready
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