Construct ABC, in which BC= 5.2cm, ACB= 45 and perimeter
of ABC is 10 cm.
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Stepofconstruction
1)DrawthebaseBC=5.6cmandatpointBmakeanangle∠×BC=30
∘
2)CutthelinesegmentBDequalto3cmfromrayBX
3)JoinCDanddrawtheperpendicularbisector,sayPQofCD
4)LetitintersectBXatapointAJoinAC
TheABCistherequiredtriangle.
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