Question

construct ∆ABC in which BC=5cm, angle B=75° and AB +AC=9 cm

Answer 1

Steps of Construction

STEP-1:- Draw a ray BX and cut off a line segment
BC =5cm from it

STEP-2:-Construct ∠XBY = 60°

STEP-3:- From BY cut off a line segment BD = 7.5 cm

STEP-4:- join cd

STEP-5:-raw the perpendicular bisector of CD, intersecting BY at a point A. 

STEP-6:- join AC
Required ABC triangle is obtained.