Question

Construct ΔABC in which BC=7 cm, ∠B =75° and AB+AC=12 cm.

Answer 1

4 Step Construction of ΔABC

Step-by-step explanation:

1.) Draw a line segment AB = 6cm.

2.) With B as the center, draw a line XB perpendicular to AB.

3.) Bisect the ABX, and further bisect the angle, thus making an ∠YBA of 75.

4.) With A as the center, draw an arc of length 6 cm, intersecting the angle YBA at C.

ABC is the required triangle.

Answer 2

Construction of triangle ABC

Step-by-step explanation:

1. Draw a line segment BC = 7 cm
2. At B construct an angle of 75 degrees and name the ray as BX. Now∠XBC is 75 degrees.
3. With B as center and radius of 12 cm (AB + AC), draw an arc that cuts the ray at D.
4. Join CD.
5. Now, draw the perpendicular bisector of CD that intersects BD at A.
6. Join AC.
7. Triangle ABC is the required triangle.

Please refer to the attached picture for the diagram.