Construct ΔABC in which BC = 7 cm, ∠B = 75° and AB + AC = 12 cm.
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Given :
In ∆ ABC ,
BC = 7 cm
^B = 75°
AB + AC = 12 cm
Therefore , AB = 6 cm
AC = 6 cm
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Step-by-step explanation:
STEPS OF CONSTRUCTION :
Draw a ray BX and cut off a line segment BC = 7cm; from it.
At B; construct angle YBX = 75°
With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.
Join CD.
Draw Perpendicular bisector PQ of CD intersecting BD at A.
Join AC.
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