Construct ABC such that AB=6.7am,BC=5.8cm,AC=6.9cm.construct it's incircle
Answers
Answer:
Steps of Construction :
(i) Draw a line segment AB = 6 cm
(ii) With centre A and radius 6.5 cm and with
centre B and radius 5.6 cm, draw arcs
Intersecting each other at C.
(iii) Join AC and BC.
(iv) Draw the angle bisector of ∠A and ∠B
Intersecting each other at I.
(v) From I, draw I L ⊥AB
(vi) With centre I and radius IL, draw a circle
which touches the sides of △ABC internally.
On measuring the required incircle whose
radius is 1.6 cm.
(ii) Steps of Construction :
(i) Draw a line segment MN = 5.8 cm.
(ii) At M and N, draw two rays making an
angle of 30° each which intersect each other
at P.
(iii) Now draw the angle bisectors of ∠M and
∠N which intersect each other at I.
(iv) From I, draw perpendicular- IL on MN.
(v) With centre I and radius IL, draw a circle
which touches the sides of the △ PMN internally.
On measuring the required incircle and its
radius is 0.6 cm.
Step-by-step explanation:
radius of incircle = area of triangle / S
where S= (AB+BC+AC)/2
AREA OF TRIANGLE =√(S(S-AB)(S-BC)(S-AC))