Construct ABC such, that BC 4.8 m 40 , c90
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1. Draw BC=4.8 cm.
2. Construct ∠B=30 ∘ .
3. Cut off line segment BD=12 cm on the 30 ∘ line. Join C−D,
4. Draw a perpendicular bisector of CD to intersect BD at A.
5. Join A−C.6. ABC is the required triangle.
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1 .Draw a seg BC of 4.8 cm
2. Place your protractor at point B and draw a 40° angle
3. therefore∆ABC is the required triangle
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