Construct ΔABC such that BC = 6 cm. m∠B = 60, AB + CA = 9 cm. Write the steps of the constuction.
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Answer:
triangle is constructed
Step-by-step explanation:
Construct ΔABC such that BC = 6 cm. m∠B = 60, AB + CA = 9 cm.
AB^2 + BC^2 - 2AB × BCCos60 = CA^2
AB^2 + 6^2 - 2AB×6×(1/2) = (9-AB)^2
AB^2 + 36 -6AB = 81 + AB^2 - 18AB
12AB = 45
AB = 3.75
CA= 5.25
Draw a straight line BC = 6cm
now draw an angle of 60 deg at B using D
and draw a line 3.75 cm and join Awith C
or using compass draw arc of 3.75 & 5.25 cm from B & C respectively
and join intersection point of arc A with B & C
triangle is constructed
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