Math, asked by soma2588, 11 months ago

Construct ΔABC such that BC = 6 cm. m∠B = 60, AB + CA = 9 cm. Write the steps of the constuction.

Answers

Answered by amitnrw
0

Answer:

triangle is constructed

Step-by-step explanation:

Construct ΔABC such that BC = 6 cm. m∠B = 60, AB + CA = 9 cm.

AB^2 + BC^2 - 2AB × BCCos60 = CA^2

AB^2 + 6^2 - 2AB×6×(1/2) = (9-AB)^2

AB^2 + 36 -6AB = 81 + AB^2 - 18AB

12AB = 45

AB = 3.75

CA= 5.25

Draw a straight line BC = 6cm

now draw an angle of 60 deg at B using D

and draw a line 3.75 cm and join Awith C

or using compass draw arc of 3.75 & 5.25 cm from B & C respectively

and join intersection point of arc A with B & C

triangle is constructed

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