Math, asked by nikithamira6901, 9 months ago

Construct ΔPQR where PQ = 7 cm. m∠P = 30, RP - QR = 3 cm. Write the steps of the construction.

Answers

Answered by 21paras
0

Step-by-step explanation:

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Answered by AneesKakar
1

Answer:

Triangle PQR constructed.

Step-by-step explanation:

We have to draw the base line PQ= 7cm at first then from angle P we have to cut the 30 degree and make a line.

Since, PR - RQ is 3cm so from P we have to cut an arc on the line just drawn which will be opposite and cut the 3cm line from Q an make QD. Then make perpendicular bisector of QD. Then make the point R where perpendicular intercept QD.

Join RQ then the triangle PQR is formed.

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