Construct ∆ ABC such that ( BC ) = 6cm and angle ABC = 100° and angle BCA =30° Draw
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Step-by-step explanation:
Draw a triangel and address the points as A,B,C
draw the base of BC=6cm with the help of scale
- <ABC=100
- <BCA=30
now,
- <ABC+<BCA+<CAB=180(Angle sum property)
100+30+<CAB=180
130+<CAB=180
<CAB=180-130
<CAB=50 degree
answer of angle <CAB=50
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