Question

Construct Δ ABC with AB = 3cm, BC = 4cm and AC = 5cm.

Answer 1

For constructing Δ

1.Draw a line from A to B ( AB = 3 cm. )using scale.

2.Now keep bow compass at A and extend it till 5 cm. and draw a arc M.

3.Similarly keep bow compass at B and extend it till 4 cm. and draw a arc N such that its intersect with the M.

4.Give name point of intersection C.

5.By joining point AC and AB we got right angle ΔABC.

Answer 2

It is given that ,

In ∆ABC ,

AB = 3 cm , BC = 4 cm , AC = 5 cm

Draw a rough diagram .

Construction Steps :

1 ) Draw BC = 4 cm line segment.

2 ) Take B as center with radius 3 cm

draw an arc .

3 ) Take C as center with radius 5 cm

draw another arc such that which

intersects the first arc at A .

4 ) Join A to B and C .

Required ∆ABC formed.

I hope this helps you.

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