Question

Construct ΔABC with AB= 5cm Angle A=60° and BC+AC =12 cm

Answer 1

Answer:

Given, in ΔABC, BC=5 cm, ∠B=60° and AC + AB=7.5 cm.

To construct the triangle ABC use the following steps.

1.Draw the base BC = 5 cm.

2.At the point B make an ∠XBC = 60°.

3.Cut a line segment BD equal to AB + AC = 7.5 cm from the ray BX.

4.Join DC.

5.Make an ∠DCY = ∠BDC.

6.Let CY intersect BX at A.

Then, ΔABC is the required triangle.