Question

Construct an ∠ = 90° using compass and ruler. Draw QO the bisector of ∠ .Measure

∠ and ∠ . Are they equal​

Answer 1

Step-by-step explanation:

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Steps constructions:

Steps constructions:1. Construct a line segment BC

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.3. Taking D as a center and the radius, as taken in step 2, construct an arc that cuts the previous arc at point E.

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.3. Taking D as a center and the radius, as taken in step 2, construct an arc that cuts the previous arc at point E.4. Taking E as a center and the same radius, construct one more arc which cuts the first arc at point F.

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.3. Taking D as a center and the radius, as taken in step 2, construct an arc that cuts the previous arc at point E.4. Taking E as a center and the same radius, construct one more arc which cuts the first arc at point F.5. Taking E and F as center and radii equal to more than half the distance between Eat F, construct arc which cut each other at point L.

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.3. Taking D as a center and the radius, as taken in step 2, construct an arc that cuts the previous arc at point E.4. Taking E as a center and the same radius, construct one more arc which cuts the first arc at point F.5. Taking E and F as center and radii equal to more than half the distance between Eat F, construct arc which cut each other at point L.6. Now join BL to meet EF at M and produce to point A. Then ∠ABC=90∘

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.3. Taking D as a center and the radius, as taken in step 2, construct an arc that cuts the previous arc at point E.4. Taking E as a center and the same radius, construct one more arc which cuts the first arc at point F.5. Taking E and F as center and radii equal to more than half the distance between Eat F, construct arc which cut each other at point L.6. Now join BL to meet EF at M and produce to point A. Then ∠ABC=90∘7. Construct BP, the bisector of angle ABC. [with D,M as centers and suitable radius construct two arc meeting each other at Qproduced it to P]

Steps constructions:1. Construct a line segment BC2. With center B, construct an arc of any suitable radius, which cuts BC at the point D.3. Taking D as a center and the radius, as taken in step 2, construct an arc that cuts the previous arc at point E.4. Taking E as a center and the same radius, construct one more arc which cuts the first arc at point F.5. Taking E and F as center and radii equal to more than half the distance between Eat F, construct arc which cut each other at point L.6. Now join BL to meet EF at M and produce to point A. Then ∠ABC=90∘7. Construct BP, the bisector of angle ABC. [with D,M as centers and suitable radius construct two arc meeting each other at Qproduced it to P]⟹∠PBC=45∘   [∴BP is bisector of ∠ABC]

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