construct an angle of 90 degree at the internal point of a given Ray and justify the construction
Answers
Mark as Brainlliest
Here is ur Answer
We need to construct two adjacent angles each of 60 degrees and bisect the second one to construct 90 degrees.
Steps of Construction:
Construct an angle of 90 at the initial point of a given ray and justify the construction
(i) Draw a ray PQ.
(ii) To construct 60° angle, draw an arc of any radius with P as center intersecting PQ at R. With R as center and same radius, draw an arc intersecting the previous arc at S. ∠SPQ = 60°
(iii) To construct adjacent 60°, with S as the center and same radius, draw an arc as before intersecting the initial arc at T. ∠TPS will be 60°
(iv) To bisect ∠TPS, with T and S as centers and radius more than half of TS, draw two arcs to intersect each other at U. Join P and U.
∠UPS = 1/2 ∠TPS = 30°
(v) Now we get ∠UPQ of 90° at the initial point P.
∠UPQ = ∠UPS + ∠SPR
= 30° + 60°
= 90°
I hope it will help you
pls mark me as brainilest.
Thank you :)