Question

Construct an equilateral triangle ABC of side 5cm. Measure its three angle . Are they equal ? What other name can you give to this triangle ? Also , construct perpendicular bisect of side BC and angle A​

Answer 1

Answer:

hey

Step-by-step explanation:

Steps of construction:

1. Draw equilateral ΔABC according to the given measures.

2. Draw the perpendicular CD from C to AB.

Now CD is the height h=

5

2

−(

2

5

)

2

=

2

5

3

=4.3 cm of the triangle. Draw perpendicular bisector of CD to get DE = h/2.

Area of ΔABC=

2

1

×AB×h=AB×

2

h

To draw a square of area AB×(h/2), the side of the square should be

AB×

2

h

=

2

5(3)

4

1

=3.3 cm.

Steps of construction:

1. Draw PQ=AB+

2

h

=3.3 cm.

2. At the point Q and P, draw angles of 90˚ on the same side of PQ.

3. Cut those perpendicular lines at 3.3 cm at R and S.

4. Join RS.

5. Area of square PQ×QR=3.3×3.3 cm

2

≈10.89 cm

2